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Get access to the detailed solutions to the previous year's questions asked in XAT exam.
Let '100x' be the number of students who joined XCRI last year.
Let 'a', 'b', 'c' and d be the number of students who play 1 game, 2 games, 3 games and 4 games respectively.
Therefore,
a+b+c+d = 100x ... (1)
a+2b+3c+4d = 70x+75x+80x+85x
a+2b+3c+4d = 310x ... (2)
By equation (2) - (1)
b+2c+3d = 210x
We have to minimize 'd' for that we have to maximize c. But c ≤ 100x
At cmax = 90x, dmin = 10x
Therefore, we can say that the minimum percentage of students who play all four games = 10%.